Below are detailed steps. Minimum Cost to Cut a Stick 1548. from the example below, what is the maximum number of calls that were active at the same time: If anyone knows an alogrithm or can point me in the right direction, I 29, Sep 17. Lets include our helper function inside our code. Using Kolmogorov complexity to measure difficulty of problems? Not the answer you're looking for? Sample Output. . While processing all events (arrival & departure) in sorted order. When we can use brute-force to solve the problem, we can think whether we can use 'greedy' to optimize the solution. Given a list of intervals of time, find the set of maximum non-overlapping intervals. 359 , Road No. . Skip to content Toggle navigation. the Cosmos. Each subarray will be of size k, and we want to maximize the . Given a list of intervals of time, I need to find the set of maximum non-overlapping intervals. -> There are possible 6 interval pairs. Output . The maximum overlapping is 4 (between (1, 8), (2, 5), (5, 6) and (3, 7)) Recommended Practice Maximum number of overlapping Intervals Try It! which I am trying to find the maximum number of active lines in that So rather than thinking in terms of reading the whole list and sorting we only need to read in order of start time and merge from a min-heap of the end times. interval. As per your logic, we will ignore (3,6) since it is covered by its predecessor (1,6). Please refresh the page or try after some time. LeetCode--Insert Interval 2023/03/05 13:10. We are left with (1,6),(5,8) , overlap between them =1. On those that dont, its helpful to assign one yourself and imagine these integers as start/end minutes, hours, days, weeks, etc. Why do small African island nations perform better than African continental nations, considering democracy and human development? We can visualize the interval input as the drawing below (not to scale): Now that we understand what intervals are and how they relate to each other visually, we can go back to our task of merging all overlapping intervals. In a given array nums of positive integers, find three non-overlapping subarrays with maximum sum. If you've seen this question before in leetcode, please feel free to reply. If Yes, combine them, form the new interval and check again. Intervals like [1,2] and [2,3] have borders "touching" but they don't overlap each other. What is the purpose of this D-shaped ring at the base of the tongue on my hiking boots? Maximum overlapping interval Maximum overlapping interval Given n intervals [si, fi], find the maximum number of overlapping intervals. Welcome to the 3rd article in my series, Leetcode is Easy! GitHub Gist: instantly share code, notes, and snippets. But for algo to work properly, ends should come before starts here. Program for array left rotation by d positions. Thanks again, Finding (number of) overlaps in a list of time ranges, http://rosettacode.org/wiki/Max_Licenses_In_Use, How Intuit democratizes AI development across teams through reusability. Example 2: Maximum Sum of 3 Non-Overlapping Subarrays. Check our Website: https://www.takeuforward.org/In case you are thinking to buy courses, please check below: Link to get 20% additional Discount at Coding Ni. Constraints: 1 <= intervals.length <= 10 4 If you find any difficulty or have any query then do COMMENT below. Browse other questions tagged, Where developers & technologists share private knowledge with coworkers, Reach developers & technologists worldwide. Non-overlapping Intervals 436. And the complexity will be O(n). be careful: It can be considered that the end of an interval is always greater than its starting point. Are there tables of wastage rates for different fruit and veg? In my opinion greedy algorithm will do the needful. We have individual intervals contained as nested arrays. 1401 Circle and Rectangle Overlapping; 1426 Counting Elements; 1427 Perform String Shifts; r/leetcode Small milestone, but the start of a journey. 19. Merge Overlapping Intervals Using Nested Loop. Input: Intervals = {{6,8},{1,9},{2,4},{4,7}}Output: {{1, 9}}. To learn more, see our tips on writing great answers. The idea is to store coordinates in a new vector of pair mapped with characters x and y, to identify coordinates. For example, the two intervals (1, 3) and (2, 4) from OP's original question overlap each other, and so in this case there are 2 overlapping intervals. Find the maximum ending value of an interval (maximum element). The idea is to sort the arrival and departure times of guests and use the merge routine of the merge sort algorithm to process them together as a single sorted array of events. Save my name, email, and website in this browser for the next time I comment. Given a collection of intervals, merge all overlapping intervals. Maximum Sum of 3 Non-Overlapping Subarrays . Now consider the intervals (1, 100), (10, 20) and (30, 50). How can I use it? # class Interval(object): # def __init__(self, s=0, e=0): # self . Off: Plot No. Following is the C++, Java, and Python program that demonstrates it: No votes so far! finding a set of ranges that a number fall in. . Cookies Drug Meaning. Doesn't works for intervals (1,6),(3,6),(5,8). Example 1: Input: N = 5 Entry= {1, 2,10, 5, 5} Exit = {4, 5, 12, 9, 12} Output: 3 5 Explanation: At time 5 there were guest number 2, 4 and 5 present. Now check If the ith interval overlaps with the previously picked interval then modify the ending variable with the maximum of the previous ending and the end of the ith interval. Given a list of time ranges, I need to find the maximum number of overlaps. If No, put that interval in the result and continue. pair of intervals; {[s_i,t_i],[s_j,t_j]}, with the maximum overlap among all the interval pairs. Enter your email address to subscribe to new posts. ORA-00020:maximum number of processes (500) exceeded . Maximum number of overlapping for each intervals during its range, Looking for an efficient Interval tree Algorithm. Sort the intervals based on the increasing order of starting time. This approach cannot be implemented in better than O(n^2) time. Non-overlapping Intervals . Staging Ground Beta 1 Recap, and Reviewers needed for Beta 2, Finding longest overlapping interval pair, Finding all possible combinations of numbers to reach a given sum. Approach: The idea is to store coordinates in a new vector of pair mapped with characters 'x' and 'y', to identify coordinates. This is done by increasing the value at the arrival time by one and decreasing the value after departure time by one. Note that I don't know which calls were active at this time ;). [leetcode]689. So back to identifying if intervals overlap. 80, Jubilee Hills, Hyderabad-500033 router bridge mode explained + 91 40 2363 6000 how to change kindle book cover info@vspl.in Input To learn more, see our tips on writing great answers. 01:20. Why are physically impossible and logically impossible concepts considered separate in terms of probability? Since I love numbered lists, the problem breaks down into the following steps. The idea is, in sorted array of intervals, if interval[i] doesnt overlap with interval[i-1], then interval[i+1] cannot overlap with interval[i-1] because starting time of interval[i+1] must be greater than or equal to interval[i]. But in term of complexity it's extremely trivial to evaluate: it's linear in term of the total duration of the calls. Rafter Span Calculator, Among those pairs, [1,10] & [3,15] has the largest possible overlap of 7. Note that the start time and end time is inclusive: that is, you cannot attend two events where one of them starts and the other ends at the same time. Solution 1: Brute force Approach: First check whether the array is sorted or not.If not sort the array. Share Cite Follow answered Aug 21, 2013 at 0:28 utopcell 61 2 Add a comment 0 . We initialize this second array with the first interval in our input intervals. The maximum number of guests is 3. 07, Jul 20. input intervals : {[1, 10], [2, 6], [3,15], [5, 9]}. Output: only one integer . What is \newluafunction? Memory Limit: 256. If the current interval is not the first interval and it overlaps with the previous interval. Then for each element (i) you see for all j < i if, It's amazing how for some problems solutions sometimes just pop out of one mind and I think I probably the simplest solution ;). :rtype: int Given an array of arrival and departure times from entries in the log register, find the point when there were maximum guests present in the event. Be the first to rate this post. end points = {{2, 3}, {1, 4}, {4, 6}, {8, 9}}Intervals [2, 3] and [1, 4] overlap. I was able to find many procedures regarding interval trees, maximum number of overlapping intervals and maximum set of non-overlapping intervals, but nothing on this problem. So range interval after sort will have 5 values at 2:25:00 for 2 starts and 3 ends in a random order. Time complexity = O(nlgn), n is the number of the given intervals. A simple approach is to start from the first interval and compare it with all other intervals for overlapping, if it overlaps with any other interval, then remove the other interval from the list and merge the other into the first interval. By following this process, we can keep track of the total number of guests at any time (guests that have arrived but not left). 2023. The idea to solve this problem is, first sort the intervals according to the starting time. Two Pointers (9) String/Array (7) Design (5) Math (5) Binary Tree (4) Matrix (1) Topological Sort (1) Saturday, February 7, 2015. Thanks for contributing an answer to Stack Overflow! Non-overlapping Intervals maximum overlapping intervals leetcode (4) First of all, I think the maximum is 59, not 55. Weve written our helper function that returns True if the intervals do overlap, which allows us to enter body of the if statement and #merge. Step 2: Initialize the starting and ending variable as -1, this indicates that currently there is no interval picked up. The intervals partially overlap. callStart times are sorted. Count Ways to Group Overlapping Ranges . Can we do better? Maximum number of overlapping Intervals. Merge Intervals. An interval f or the purpose of Leetcode and this article is an interval of time, represented by a start and an end. Today I'll be covering the Target Sum Leetcode question. What is an efficient way to get the max concurrency in a list of tuples? Our pseudocode will look something like this. Algorithm for finding Merge Overlapping Intervals Step 1: Sort the intervals first based on their starting index and then based on their ending index. Do NOT follow this link or you will be banned from the site! Pedestrian 1 entered at time 1 and exited at time 3 and so on.. Find the interval during which maximum number of pedestrians were crossing the road. As always, Ill end with a list of questions so you can practice and internalize this patten yourself. Complexity: O(n log(n)) for sorting, O(n) to run through all records. Whats the grammar of "For those whose stories they are"? Find centralized, trusted content and collaborate around the technologies you use most. You may assume that the intervals were initially sorted according to their start times. from the example below, what is the maximum number of calls that were active at the same time: r/leetcode Google Recruiter. If the intervals do not overlap, this duration will be negative. def maxOverlap(M, intervals): intervalPoints = [] for interval in intervals: intervalPoints.append ( (interval [0], -1)) intervalPoints.append ( (interval [1], 1)) intervalPoints.sort () maxOverlap = 0 maxOverlapLocation = 0 overlaps = 0 for index, val in intervalPoints: overlaps -= val if overlaps > maxOverlap: maxOverlap = overlaps Non-Leetcode Questions Labels. Acidity of alcohols and basicity of amines. (Leetcode Premium) Maximum Depth of Binary Tree Same Tree Invert/Flip Binary Tree Binary Tree Maximum Path . We merge interval A and interval B into interval C. Interval A completely overlaps interval B. Interval B will be merged into interval A. The nature of simulating nature: A Q&A with IBM Quantum researcher Dr. Jamie We've added a "Necessary cookies only" option to the cookie consent popup. classSolution { public: Maximum Intervals Overlap. For example, given following intervals: [0600, 0830], [0800, 0900], [0900, 1100], [0900, 1130], [1030, 1400], [1230, 1400] Also it is given that time have to be in the range [0000, 2400]. Why is this sentence from The Great Gatsby grammatical? If the current interval overlap with the top of the stack then, update the stack top with the ending time of the current interval. Example 1: Input: intervals = [ [1,3], [2. So for call i and (i + 1), if callEnd[i] > callStart[i+1] then they can not go in the same array (or platform) put as many calls in the first array as possible. After the count array is filled with each event timings, find the maximum elements index in the count array. The reason for the connected component search is that two intervals may not directly overlap, but might overlap indirectly via a third interval. acknowledge that you have read and understood our, Data Structure & Algorithm Classes (Live), Data Structure & Algorithm-Self Paced(C++/JAVA), Android App Development with Kotlin(Live), Full Stack Development with React & Node JS(Live), GATE CS Original Papers and Official Keys, ISRO CS Original Papers and Official Keys, ISRO CS Syllabus for Scientist/Engineer Exam, Sort an almost sorted array where only two elements are swapped, Find the point where maximum intervals overlap, Largest Rectangular Area in a Histogram using Stack, Largest Rectangular Area in a Histogram using Segment Tree, Persistent Segment Tree | Set 1 (Introduction), Longest prefix matching A Trie based solution in Java, Pattern Searching using a Trie of all Suffixes, Ukkonens Suffix Tree Construction Part 1, Ukkonens Suffix Tree Construction Part 2, Ukkonens Suffix Tree Construction Part 3, Ukkonens Suffix Tree Construction Part 4, Ukkonens Suffix Tree Construction Part 5, Write a program to reverse an array or string, Largest Sum Contiguous Subarray (Kadane's Algorithm). The newly merged interval will be the minimum of the front and the maximum . By using our site, you Maximum Frequency Stack Leetcode Solution - Design stack like data . You can represent the times in seconds, from the beginning of your range (0) to its end (600). To iterate over intervals, we need to introduce a second array to store intervals that we have already checked and potentially merged. Sample Input. In the end, number of arrays are maximum number of overlaps. increment numberOfCalls if time value marked as Start, decrement numberOfCalls if time value marked as End, keep track of maximum value of numberOfCalls during the process (and time values when it occurs), Take the least of the start times and the greatest of the end times (this is your range R), Take the shortest call duration -- d (sorting, O(nlog n)), Create an array C, of ceil(R/d) integers, zero initialize, Now, for each call, add 1 to the cells that define the call's duration O(n * ceil(R/d)), Loop over the array C and save the max (O(n)). See the example below to see this more clearly. ie. We set the last interval of the result array to this newly merged interval. Address: Women Parliamentary Caucus, 1st floor, National Assembly Secretariat, Islamabad, Powered by - Westminster Foundation for Democracy, Media Consultation on Gender and Climate Change Parliamentary Initiatives, General Assembly Session of WPC 26th January 2021, The role of Women Parliamentarians in Ending violence against women. Does ZnSO4 + H2 at high pressure reverses to Zn + H2SO4? Once we have iterated over and checked all intervals in the input array, we return the results array. In this problem, we assume that intervals that touch are overlapping (eg: [1,5] and [5,10] should be merged into [1, 10]). Repeat the same steps for the remaining intervals after the first CodeFights - Comfortable Numbers - Above solution requires O(max-min+1) extra space. Making statements based on opinion; back them up with references or personal experience. The time complexity of the above solution is O(n), but requires O(n) extra space. Software Engineer III - Machine Learning/Data @ Walmart (May 2021 - Present): ETL of highly sensitive store employees data for NDA project: Coded custom Airflow DAG & Python Operators to auth with . How can I pair socks from a pile efficiently? Find Right Interval 437. Does a summoned creature play immediately after being summoned by a ready action? Given different intervals, the task is to print the maximum number of overlap among these intervals at any time. Non-overlapping Intervals 436. Example 2: Input: intervals = [ [1,2], [1,2], [1,2]] Output: 2 Explanation: You need to remove two [1,2] to make the rest of the intervals non-overlapping. Return the minimum number of taps that should be open to water the whole garden, If the garden cannot be watered return -1. How to tell which packages are held back due to phased updates. Now, traverse through all the intervals, if we get two overlapping intervals, then greedily choose the interval with lower end point since, choosing it will ensure that intervals further can be accommodated without any overlap. You may assume the interval's end point is always bigger than its start point. By clicking Accept all cookies, you agree Stack Exchange can store cookies on your device and disclose information in accordance with our Cookie Policy. The picture below will help us visualize. it may be between an interval and a later interval that it completely covers. Repeat the same steps for the remaining intervals after the first. Example 1: Input: intervals = [ [1,3], [2,6], [8,10], [15,18]] Output: [ [1,6], [8,10], [15,18]] Explanation: Since intervals [1,3] and [2,6] overlap, merge them into [1,6]. PLEASE help our channel by SUBSCRIBING and LIKE our video if you found it helpfulCYA :)========================================================================Join this channel to get access to perks:https://www.youtube.com/channel/UCnxhETjJtTPs37hOZ7vQ88g/joinINSTAGRAM : https://www.instagram.com/surya.pratap.k/SUPPORT OUR WORK: https://www.patreon.com/techdose LinkedIn: https://www.linkedin.com/in/surya-pratap-kahar-47bb01168 WEBSITE: https://techdose.co.in/TELEGRAM Channel LINK: https://t.me/codewithTECHDOSETELEGRAM Group LINK: https://t.me/joinchat/SRVOIxWR4sRIVv5eEGI4aQ =======================================================================CODE LINK: https://gist.github.com/SuryaPratapK/1576423059efee681122c345acfa90bbUSEFUL VIDEOS:-Interval List Intersections: https://youtu.be/Qh8ZjL1RpLI Approach: Sort the intervals, with respect to their end points. In our example, the array is sorted by start times but this will not always be the case. We will check overlaps between the last interval of this second array with the current interval in the input. As recap, we broke our problem down into the following steps: Key points to remember for each step are: Last but not least, remember that the input intervals must be sorted by start time for this process to work. A very simple solution would be check the ranges pairwise. Note that entries in register are not in any order. :type intervals: List[Interval] Maybe I would be able to use the ideas given in the above algorithms, but I wasn't able to come up with one. Are there tables of wastage rates for different fruit and veg? . We can try sort! Merge overlapping intervals in Python - Leetcode 56. How to take set difference of two sets in C++? If the next event is arrival, increase the number of guests by one and update the maximum guests count found so far if the current guests count is more. Given a collection of intervals, find the minimum number of intervals you need to remove to make the rest of the intervals non-overlapping.Note: You may assume the interval's end point is always big. This is certainly very inefficient. By clicking Post Your Answer, you agree to our terms of service, privacy policy and cookie policy. We then subtract the front maximum from the back minimum to figure out how many minutes these two intervals overlap. Solution: The brute force way to approach such a problem is select each interval and check from all the rests if it they can be combined? An interval for the purpose of Leetcode and this article is an interval of time, represented by a start and an end. How do/should administrators estimate the cost of producing an online introductory mathematics class? Minimum Cost to Cut a Stick 1239-maximum-length-of-a-concatenated-string-with-unique-characters . LeetCode Solutions 2580. Then T test cases follow. Given a list of time ranges, I need to find the maximum number of overlaps. Then repeat the process with rest ones till all calls are exhausted. Do not print the output, instead return values as specified. 0053 Maximum Subarray; 0055 Jump Game; 0056 Merge Intervals; 0066 Plus One; 0067 Add Binary; 0069 Sqrt(x) . Return the result as a list of indices representing the starting position of each interval (0-indexed). For example, we might be given an interval [1, 10] which represents a start of 1 and end of 10. ie. If there are multiple answers, return the lexicographically smallest one. Example 1: Input: [ [1,2], [2,3], [3,4], [1,3] ] Output: 1 Explanation: [1,3] can be removed and the rest of intervals are non-overlapping. So lets take max/mins to figure out overlaps. The explanation: When we traverse the intervals, for each interval, we should try our best to keep the interval whose end is smaller (if the end equal, we should try to keep the interval whose start is bigger), to leave more 'space' for others. Traverse the given input array, get the starting and ending value of each interval, Insert into the temp array and increase the value of starting time by 1, and decrease the value of (ending time + 1) by 1. so, the required answer after merging is [1,6], [8,10], [15,18]. Once you have that stream of active calls all you need is to apply a max operation to them. 494. Although (1, 5) and (6, 10) do not directly overlap, either would overlap with the other if first merged with (4, 7). The time complexity of this approach is O(n.log(n)) and doesnt require any extra space, where n is the total number of guests. ), n is the number of the given intervals. The newly merged interval will be the minimum of the front and the maximum of the end. 5 1 2 9 5 5 4 5 12 9 12. Let the array be count []. INPUT: First line No of Intervals. Some problems assign meaning to these start and end integers. This question equals deleting least intervals to get a no-overlap array. What is the purpose of this D-shaped ring at the base of the tongue on my hiking boots? So the number of overlaps will be the number of platforms required. How to handle a hobby that makes income in US. No more overlapping intervals present. Remember, intervals overlap if the front back is greater than or equal to 0. Site design / logo 2023 Stack Exchange Inc; user contributions licensed under CC BY-SA. Find minimum platforms needed to avoid delay in the train arrival. Then fill the count array with the guests count using the array index to store time, i.e., for an interval [x, y], the count array is filled in a way that all values between the indices x and y are incremented by 1. I think an important element of good solution for this problem is to recognize that each end time is >= the call's start time and that the start times are ordered. Following is a dataset showing a 10 minute interval of calls, from which I am trying to find the maximum number of active lines in that interval. Since this specific problem does not specify what these start/end integers mean, well think of the start and end integers as minutes. Sort all your time values and save Start or End state for each time value. Find the time at which there are maximum guests in the party. [Leetcode 56] Merge Intervals. For the rest of this answer, I'll assume that the intervals are already in sorted order. . Follow the steps mentioned below to implement the approach: Below is the implementation of the above approach: Time complexity: O(N*log(N))Auxiliary Space: O(N). 15, Feb 20. count[i min]++; 4) Find the index of maximum element in count array. 685 26K views 2 years ago DURGAPUR This video explains the problem of non-overlapping intervals.This problem is based on greedy algorithm.In this problem, we are required to find the minimum. We care about your data privacy. In other words, if interval A overlaps with interval B, then I add both A and B to the resulting set of intervals that overlap. set of n intervals; {[s_1,t_1], [s_2,t_2], ,[s_n,t_n]}. Read our, // Function to find the point when the maximum number of guests are present in an event, // Find the time when the last guest leaves the event, // fill the count array with guest's count using the array index to store time, // keep track of the time when there are maximum guests, // find the index of the maximum element in the count array, // Function to find the point when the maximum number of guests are, # Function to find the point when the maximum number of guests are present in an event, # Find the time when the last guest leaves the event, # fill the count array with guest's count using the array index to store time, # keep track of the time when there are maximum guests, # find the index of the maximum element in the count array, // sort the arrival and departure arrays in increasing order, // keep track of the total number of guests at any time, // keep track of the maximum number of guests in the event, /* The following code is similar to the merge routine of the merge sort */, // Process all events (arrival & departure) in sorted order, // update the maximum count of guests if needed, // Function to find the point when the maximum number of guests are present, // keep track of the max number of guests in the event, # sort the arrival and departure arrays in increasing order, # keep track of the total number of guests at any time, # keep track of the maximum number of guests in the event, ''' The following code is similar to the merge routine of the merge sort ''', # Process all events (arrival & departure) in sorted order, # update the maximum count of guests if needed, // perform a prefix sum computation to determine the guest count at each point, # perform a prefix sum computation to determine the guest count at each point, sort the arrival and departure times of guests, Convert an infix expression into a postfix expression. Signup and start solving problems. Then Entry array and exit array. The maximum non-overlapping set of intervals is [0600, 0830], [0900, 1130], [1230, 1400]. Will fix . We must include [2, 3] because if [1, 4] is included thenwe cannot include [4, 6].Input: intervals[][] = {{1, 9}, {2, 3}, {5, 7}}Output:[2, 3][5, 7]. it may be between an interval and the very next interval that it. You may assume the interval's end point is always bigger than its start point. The time complexity of this approach is quadratic and requires extra space for the count array. Count points covered by given intervals. Given a set of N intervals, the task is to find the maximal set of mutually disjoint intervals. Input: intervals = [ [1,2], [2,3], [3,4], [1,3]] Output: 1 Explanation: [1,3] can be removed and the rest of the intervals are non-overlapping. Take a new data structure and insert the overlapped interval. A simple approach is to start from the first interval and compare it with all other intervals for overlapping, if it overlaps with any other interval, then remove the other interval from the list and merge the other into the first interval. would be grateful. Today well be covering problems relating to the Interval category. Merge Intervals: If we identify an overlap, the new merged range will be the minimum of starting times and maximum of ending times. How do/should administrators estimate the cost of producing an online introductory mathematics class? Thank you! Return this maximum sum. Input: v = {{1, 2}, {2, 4}, {3, 6}}Output: 2The maximum overlapping is 2(between (1 2) and (2 4) or between (2 4) and (3 6)), Input: v = {{1, 8}, {2, 5}, {5, 6}, {3, 7}}Output: 4The maximum overlapping is 4 (between (1, 8), (2, 5), (5, 6) and (3, 7)). Notice that if there is no overlap then we will always see difference in number of start and number of end is equal to zero. How to Check Overlaps: The duration of the overlap can be calculated by back minus front, where front is the maximum of both starting times and back is the minimum of both ending times. """, S(? Now, there are two possibilities for what the maximum possible overlap might be: We can cover both cases in O(n) time by iterating over the intervals, keeping track of the following: and computing each interval's overlap with L. So the total cost is the cost of sorting the intervals, which is likely to be O(n log n) time but may be O(n) if you can use bucket-sort or radix-sort or similar. We can obviously see intervals overlap if the end time of interval A is after the begin time of interval B. Therefore we will merge these two and return [1,4],[6,8], [9,10]. A-143, 9th Floor, Sovereign Corporate Tower, We use cookies to ensure you have the best browsing experience on our website. How do I generate all permutations of a list? How can I check before my flight that the cloud separation requirements in VFR flight rules are met? The Most Similar Path in a Graph 1549. . This algorithm returns (1,6),(2,5), overlap between them =4. the greatest overlap we've seen so far, and the relevant pair of intervals. Delete least intervals to make non-overlap 435. . We can avoid the use of extra space by doing merge operations in place. Note: You only need to implement the given function. Given an array of arrival and departure times from entries in the log register, find the point when there were maximum guests present in the event. Now linearly iterate over the array and then check for all of its next intervals whether they are overlapping with the interval at the current index. Activity-Selection: given a set of activities with start and end time (s, e), our task is to schedule maximum non-overlapping activities or remove minimum number of intervals to get maximum non .